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1 g of a metal (specific heat = 0.06 cal/g), combines with oxygen to form 1.08 g of oxide. What is the atomic mass of metal? Also report its valency. |
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Answer» Eq. of metal = Eq. of oxygen wt. of metal = 1 g, wt. of oxygen = 1.08 - 1 = 0.08 g 1/Emetal = 0.08/8 Emetal = 100 Also App. at.wt. x sp. heat = 6.4 App. at. wt. = 6.4/0.06 = 106.67 Valence = at. wt./ E. wt. = 106.67/100 = 1 (integer ) exact at. wt. = E x valence = 100 x 1 = 100 |
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