1 g of a metal required 50 mL of 0.5 N HCl to dissovle it. The equivalent mass of the metal is :

1 g of a metal required 50 mL of 0.5 N HCl to dissovle it. The equival

1.	1 g of a metal required 50 mL of 0.5 N HCl to dissovle it. The equivalent mass of the metal is :
Answer» 25 50 20 40 Solution :N//A