1.

1 g of ""_79AU^(198(t_(1//2)=65 h) gives stable mercury by beta-emission. What amount of mercury will left after 260 h?

Answer»

0.9374 g
0.3758 g
0.7586 g
0.9000 g

Solution :`_(79)AU^(198)OVERSET(-BETA)to _(80)HG^(198)`
`k=(0.0693)/(t_(1//2))=(0.0693)/(65)`
After 260 h, `" "k=(2.303)/(260)"log"(a)/(a-x)`
`(0.693)/(65)=(2.303)/(2.60)"log"(a)/(a-x)`
`x=(1498)/(1598)"g"=0.9374"g"`
Since,all radioactive reactions follow first order kinetics.


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