1.Four cards are drawn at random from a pack of52 cards. The probabili

1.	1.Four cards are drawn at random from a pack of52 cards. The probability of getting all the fourcards of the same number, is :11 106(a)(b)*(0) 5419(a) 270125
Answer» Answer: 270125 Step-by-step explanation: TOTAL No. Of cards =52 No.Of cards for each suit = 13 Total types Of French suit = 4(hearts,spades, diamonds,clubs) Prob. = Conditional case /total case For this conditional case of SELECTING all FOUR same suit,it can be either hearts or spades or clubs or diamonds So Total no. Of conditional case= no. of case of selecting all four cards of hearts suit +no.of case of selecting all four cards of spades suit +no.of case of selecting all four cards of clubs suit + no. of case of selecting all four cards of diamonds suit. = 13C4+13C4+13C4+ 13C4 =4*(13C4)=2860 Total no. of case= 52C4=270725 So, probability of GETTING all four cards of the same suit=2860/270725

1.Four cards are drawn at random from a pack of52 cards. The probability of getting all the fourcards of the same number, is :11 106(a)(b)*(0) 5419(a) 270125

Answer»

Answer:

270125

Step-by-step explanation:

TOTAL No. Of cards =52

No.Of cards for each suit = 13

Total types Of French suit = 4(hearts,spades, diamonds,clubs)

Prob. = Conditional case /total case

For this conditional case of SELECTING all FOUR same suit,it can be either hearts or spades or clubs or diamonds

So Total no. Of conditional case= no. of case of selecting all four cards of hearts suit +no.of case of selecting all four cards of spades suit +no.of case of selecting all four cards of clubs suit + no. of case of selecting all four cards of diamonds suit.

= 13C4+13C4+13C4+ 13C4

=4*(13C4)=2860

Total no. of case= 52C4=270725

So, probability of GETTING all four cards of the same suit=2860/270725

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