1. For what value of k will k+9,2k -I and 2k dieu2. For what value ofk – InterviewSolution

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1. For what value of k will k+9,2k -I and 2k dieu2. For what value ofk will the consecutive terms 2k + 1, 3k + 3 and 5 k-1 form an А.Р.? (k=the AD 5 913ー185 (153)

Answer»

2k + 1 = a3k + 3 = b5k - 1 = c

To form an AP,a + c = 2b2k + 1 + 5k - 1 = 2( 3k + 3)7k = 6k + 6k = 6

So, k = 6

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