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1. Find the molarity and molality of a 15% solution of H2SO4 when it's density is 1.10 glcm3 and molar mass = 98 amu . 2. calculate the mole fraction of ethanol and water in asample of rectified spirit which contains 46 % ethanol by mass?3. calculate the % composition in terms of mass of a solution obtained by mixing 300g of a 25% and 400 g of 40%solution by mass.4.One litre of sea wator Weight 1030g and contains about 6×10^ -3 g et dissolves O2. Calculate the concentration of dissolved oxygen in ppm?5.The density of 85% phosphoric acid is 1.70g/cm3.What is the volume of a solution that contains 17gof phosphoric acid? answer these questions.... |
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Answer» (1) 15% H₂SO₄ solution means 15 g of H₂SO₄ is present in 100 g of Water.No. of moles of H₂SO₄ = 15 g / 98 g/mol = 0.153 molWeight of solvent = 100g - 15G = 85g = 85 × 10^-3 kgMolality = Moles of solute / WEIGHT of Solvent in kg= 0.153 / (85 × 10^-3)= 1.8 mMolality of given solution is 1.8 m ……[1]Volume of solution = MASS of solution / DENSITY= 100 g / 1.1 g/cm^3= 90.90 cm^3= 0.090 LitresMolarity = Moles of solute / Volume of solution in litres= 0.153 / 0.090≈ 1.7 MMolarity of given solution is 1.7 M ……[2]Read more on Brainly.in - brainly.in/question/1301591#readmoreExplanation:(2) second question ki photo upper Hai Explanation: Rectified spirit which contains 46% ethanol by mass. In 100 g spirit has 46 grams of ethanol and 54 grams of water. Mole fraction of ethanol is 0.25. (3) Mass of solute (1) = 300g × 25/100 = 75gMass of solute (2) = 400g ×40/100 = 160gTotal masss of solute = 75+160 = 235gTotal mass of solution = 300 + 400 = 700g% composition by mass of solute = mass of solute / total mass of solution ×100 = 235/700 ×100 = 33.57% of solute% composition by mass of solvent = 100 - 33.57 = 66.43%Read more on Brainly.in - brainly.in/question/1866807#readmore |
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