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1. Find the HCF of the given polynomials:(0 14pg, 28p2. Factorise the following(ii) 8abc, 24ab2, 12a2b() 10x2- 18x3 + 14x4() 5x3y 10xyz + 15xy (i) p2x2+2x2-ac2 -app(iv) 15fx+y2-5x-y (v) (ax + by)2+ (ay - bxy? (vi) ax + by cx + bx + cy + ay(vi) 49x2 -70xy +25y2 (vii) 402 + 12ab+ 9b2(ix) 49p2 -36q2(x) 100x3-25xy2(xii) 12r3- 1422- 10x Cxiv) p2 -10p + 21(avi) 6x2-5xy - 6y2(avii) 2+ 2xy - 99y2.(rv) 2x2 - x 63. Divide as directed:(i) 15(y + 3) (y2-16) ÷ 5(y2-y-12)(ii) (3x3-6x2-24x) ÷ (1-4) (x + 2)(iii) (d-81) ÷ (x3 + 3x2 + 9x + 27) |
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Answer» HCFi) 14pq=2*7*P*q 28P^2q^2=2*2*7*p*p*q*qHCF(highest Common Factor)=2*7pq =14pq Crop only the question that you want a solution for. We will not be able to provide solutions to multiple questions. what is the sum of digits of the least multiple of13 which when divided by 6,8 and12 leaves 5,7and11 respectively as remainders |
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