1. Find the area of a triangle whose sides are in the ratio 5 12 13 an

1.	1. Find the area of a triangle whose sides are in the ratio 5 12 13 and its perimeter is 60cm.
Answer» 5x+12x+13x=6030x=60x=60÷30x=25x=1012x=2413x=26x=2cmhence5x=10 =a 12x=24 = b13x=26 = c HERON'S FORMULA AREA OF TRIANGLE = √s(s-a)(s-b)(s-c) s= perimeter /2 = 30 AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)=√30(30-10)(30-24)(30-26)=√3102102322=√3310102222=3102*2AREA OF TRIANGLE = 120 cm²

1. Find the area of a triangle whose sides are in the ratio 5 12 13 and its perimeter is 60cm.

Answer»

5x+12x+13x=6030x=60x=60÷30x=25x=1012x=2413x=26x=2cmhence5x=10 =a 12x=24 = b13x=26 = c

HERON'S FORMULA

AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)

s= perimeter /2 = 30

AREA OF TRIANGLE = √s(s-a)(s-b)(s-c)=√30(30-10)(30-24)(30-26)=√3*10*2*10*2*3*2*2=√3*3*10*10*2*2*2*2=3*10*2*2AREA OF TRIANGLE = 120 cm²