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1. Find the area of a triangle whose sides are 12 cm, 16 cm and 20 cm.

Answer»

Area of a triangle of sides a , b & c is :

√( s(s-a)(s-b)(s-c) )

where s=(a+b+c)/2

ln given trangle , s=(20+12+16)/2=48/2=24

Thus area of given triangle =

√(24(24-20)(24-12)(24-16))

=√(24×4×12×8)

=√9216

=96

Thus area of triangle of sides 20cm ,12cm and 16cm is 96cm^2

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