1.

1. Fand the total number of permutations of the letten of cach of the woreL, nd the total number of permutations of tho letterathe worsiven below) APTLE(iv) INITUTE) ARRANG(V)ENGINEERING(U) COMMEIC(vi) İNTERMEDIAIE

Answer»

1) 5!/2!=5*4*3=602)7!/2!=7*6*5*4*3=25203)8!/(2!*2!*2!)=(8*7*6*5*4*3)/(4)=50404)9!/(2!*3!)=(8*7*6*5*4)=67205) 11!/(3!*3!*2!*2!)=(11*10*9*8*7*6*5*4)/(6) =11088006)12!/(2!*2!*3!)=(12*11*10*9*8*7*6*5*4)/2 =39916800



Discussion

No Comment Found