1) Divide the sum of 65/12 and 8/3 by their difference.2) If 24 trouse

1.	1) Divide the sum of 65/12 and 8/3 by their difference.2) If 24 trousers of equal size can be prepared in 54 meters of cloth, what length of the cloth is required for each trouser?
Answer» FIRST we have to find the SUM (65/12)+(8/3) LCM of 12 and 3 is 12 Then, (65×1)/(12×1)=(65/12) and (8×4)/(3×4)=(32/12) Now, =(65+32)/12 =(97/12) Now find the difference of (65/12)−(8/3) LCM of 12 and 3 is 12 Then, (65×1)/(12×1)=(65/12) (8×4)/(3×4)=(32/12) Now, =(65−32)/12 =(33/12) Now divide (97/12)÷(33/12) =(97×12)×(12/33) =(97×12)/(12×33) =(97×1)/(1×33) =(97/33)

1) Divide the sum of 65/12 and 8/3 by their difference.2) If 24 trousers of equal size can be prepared in 54 meters of cloth, what length of the cloth is required for each trouser?

Answer»

FIRST we have to find the SUM (65/12)+(8/3)

LCM of 12 and 3 is 12

Then,

(65×1)/(12×1)=(65/12)

and (8×4)/(3×4)=(32/12)

Now,

=(65+32)/12

=(97/12)

Now find the difference of (65/12)−(8/3)

LCM of 12 and 3 is 12

Then,

(65×1)/(12×1)=(65/12)

(8×4)/(3×4)=(32/12)

Now,

=(65−32)/12

=(33/12)

Now divide (97/12)÷(33/12)

=(97×12)×(12/33)

=(97×12)/(12×33)

=(97×1)/(1×33)

=(97/33)