Saved Bookmarks
| 1. |
1+ COSXdx =... +sinx coSX |
|
Answer» ∫1−(1−2sin22x)x−sinxdx=∫2sin22xx−sinxdx =21∫sin22xx−21∫sin22x2sin2xcos2xdx =21∫x⋅cosec22x−∫cot2xdx =21[x⋅∫cosec22x−∫{DXD< |
|