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1. At what temperature 28 g of N2 will occupy a volume of 20 litres at 2 atm?(a) 300.0 K(b) 487.2 K(c) 289.6 K(d) 283.8 K​

Answer»

(b) 486.2kExplanation:PV=nRT or T=  NR PV ​   (n=  M m ​   ) Here, mass of nitrogen m=28g VOLUME of nitrogen V=20litres Pressure P=2atm ∴T=  28×0.0821 2×20×28 ​   =487.2 K.



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