1.At what height above the earth's surface does theacceleration due to

1.	1.At what height above the earth's surface does theacceleration due to gravity fall to 1% of its value atthe earth's surface?(A) R (B) 5R (C) 10R (D) 9R(show full process)
Answer» ANSWER: At 5.7600×10^7 m above the EARTH surface Explanation: $1%of g=g×10^-2 \\ Re=6.4×10^6m(Radius \: of \: earth) \\ g×10^-2=g÷{1+(h÷Re)^2} \\ Taking \: root \: both \: side \\ 1+(h÷Re)=10 \\ h÷Re=9 \\ h=Re×9 \\ h=5.7600×10^7m \\$ so it is 9R

1.At what height above the earth's surface does theacceleration due to gravity fall to 1% of its value atthe earth's surface?(A) R (B) 5R (C) 10R (D) 9R(show full process)

Answer»

At 5.7600×10^7 m above the EARTH surface

Explanation:

$1%of g=g×10^-2 \\ Re=6.4×10^6m(Radius \: of \: earth) \\ g×10^-2=g÷{1+(h÷Re)^2} \\ Taking \: root \: both \: side \\ 1+(h÷Re)=10 \\ h÷Re=9 \\ h=Re×9 \\ h=5.7600×10^7m \\$

so it is 9R

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1.At what height above the earth's surface does theacceleration due to gravity fall to 1% of its value atthe earth's surface?(A) R (B) 5R (C) 10R (D) 9R(show full process)​

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1.At what height above the earth's surface does theacceleration due to gravity fall to 1% of its value atthe earth's surface?(A) R (B) 5R (C) 10R (D) 9R(show full process)