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1)Arace track is in form of a ring whose inner circumference is 528 m and the outer circumference is 616 mFind the width of the track​

Answer»

Solution:

Outer CIRCUMFERENCE = 616 m

RADIUS R \frac{C}{2\pi}=\frac{616\times7}{2\times22}=<klux>98</klux>\ m

=98 m

Inner circumference = 528 m

Inner radius=\frac{528\times7}{2\times22}=<klux>84</klux>\ m

=84 m

Width of track = R - r

= 98 - 84 = 14 m



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