1)Arace track is in form of a ring whose inner circumference is 528 m

1.	1)Arace track is in form of a ring whose inner circumference is 528 m and the outer circumference is 616 m Find the width of the track
Answer» tion: Outer circumference = 616 m Radius R $\frac{C}{2\pi}=\frac{616\times7}{2\times22}=<klux>98</klux>\ m$ =98 m Inner circumference = 528 m Inner radius= $\frac{528\times7}{2\times22}=84\ m$ =84 m Width of TRACK = R - r = 98 - 84 = 14 m

1)Arace track is in form of a ring whose inner circumference is 528 m and the outer circumference is 616 m Find the width of the track

Answer»

tion:

Outer circumference = 616 m

Radius R $\frac{C}{2\pi}=\frac{616\times7}{2\times22}=<klux>98</klux>\ m$

=98 m

Inner circumference = 528 m

Inner radius= $\frac{528\times7}{2\times22}=84\ m$

=84 m

Width of TRACK = R - r

= 98 - 84 = 14 m

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1)Arace track is in form of a ring whose inner circumference is 528 m and the outer circumference is 616 m Find the width of the track​

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1)Arace track is in form of a ring whose inner circumference is 528 m and the outer circumference is 616 m Find the width of the track