1.

1. After paying 30 out of 40 installments of adebt of Rs. 3600/-, one third of the dept isunpaid. If the installments are forming an A.P.Then what is the first installment.(a) Rs. 50/- (b) Rs. 51/.(c) Rs. 105/- (d) Rs. 110/-

Answer»

Let the first term/instalment = Rsa.

Let the common difference between successive instalment = Rsd

Istcase:A man pays off a debt of Rs 3600 in 40 annual instalments

∴n= 40 and Sn= S40= Rs 3600Sn=n/2(2a+(n-1)d)S40=40/2(2a+39d)3600=20(2a+39d)2a+39d=180...(1)IIndcase:Man dies, leaving one-third of the debt unpaid.

Now debt unpaid1/3*3600=1200∴ Debt paid by Man in 30 instalments = Total debt paid – Debt unpaid

= 3600 – 1200 = Rs 2400

Heren= 30 and Sn= S30= 2400

S30=30/2(2a+29d)160=2a+29d2a+28d=60

Subtracting equation (2) from equation (1), we get

(2a+ 39d) – (2a+ 29d) = 180 – 160

⇒39d– 29d= 20

⇒10d= 20

⇒d= 2

Putting value ofdin (1), we get

2a+ 39d= 180

⇒2a+ 39 × 2 = 180

⇒2a= 180 – 78

2a= 102

⇒a= 51 Rs

Therefore, the first instalment paid by man = Rs 51

Th

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