1. A truck starts from rest and accelerates at 3 m/s^2for 5 s and then

1.	1. A truck starts from rest and accelerates at 3 m/s^2for 5 s and then continues with constant velocity.Calculate the distance covered in 15 s since it startsfrom rest.[Ans : 187.5 m]
Answer» Answer: 187.5 m Explanation: DISTANCE covered in first 5 s S = ut + 0.5at² = (0 × 5) + (0.5 × 3 × 5²) = 75/2 m = 37.5 m Velocity at the end of 5 s v = u + at = 0 m/s + (3 m/s² × 5 s) = 15 m/s From now, TRUCK is MOVING with a uniform velocity of 15 m/s Distance covered in rest of the 10 s D = SPEED × Time = 15 m/s × 10 s = 150 m Total distance covered = 37.5 m + 150 m = 187.5 m

1. A truck starts from rest and accelerates at 3 m/s^2for 5 s and then continues with constant velocity.Calculate the distance covered in 15 s since it startsfrom rest.[Ans : 187.5 m]

Answer»

Answer:

187.5 m

Explanation:

DISTANCE covered in first 5 s

S = ut + 0.5at²

= (0 × 5) + (0.5 × 3 × 5²)

= 75/2 m

= 37.5 m

Velocity at the end of 5 s

v = u + at

= 0 m/s + (3 m/s² × 5 s)

= 15 m/s

From now, TRUCK is MOVING with a uniform velocity of 15 m/s

Distance covered in rest of the 10 s

D = SPEED × Time

= 15 m/s × 10 s

= 150 m

Total distance covered = 37.5 m + 150 m

= 187.5 m

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1. A truck starts from rest and accelerates at 3 m/s^2for 5 s and then continues with constant velocity.Calculate the distance covered in 15 s since it startsfrom rest.[Ans : 187.5 m]​

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1. A truck starts from rest and accelerates at 3 m/s^2for 5 s and then continues with constant velocity.Calculate the distance covered in 15 s since it startsfrom rest.[Ans : 187.5 m]