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1.A particle ismoving up an inclined plane .Its velocity changes from 15m/s to 10m/s in two seconds . What is its acceleration?

Answer»

Answer

  • Acceleration = - 2.5 m/s²

Given

  • A PARTICLE is moving up an inclined plane .Its velocity changes from 15 m/s to 10 m/s in two seconds

To Find

  • Acceleration

Concept Used

Acceleration

  • It is defined as rate of CHANGE in velocity

\bigstar \bf \;\;\; Acceleration=\dfrac{Change\ in\ velocity}{Time}

  • SI unit of Acceleration is m/s²
  • SI unit of velocity is m/s
  • SI unit of Time is second

Solution

Initial velocity , u = 15 m/s

Final velocity , V = 10 m/s

Time , t = 2 s

Acceleration , a = ? m/s²

Now , Apply formula .

\implies \rm Acceleration=\dfrac{Change\ in\ velocity}{Time}\\\\\implies \rm a=\dfrac{v-u}{t}\\\\\implies \rm a=\dfrac{10-15}{2}\\\\\implies \rm a=\dfrac{-5}{2}\\\\\implies \rm a=-2.5\ m/s^2

- ve sign of acceleration denotes RETARDATION / deceleration



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