Given: ∠C = 90˚, AB = 9m, BC = 12 m, CD = 5m and AD = 8m.To Find: Area of quadrilateral ABCD.Concept Used:If sides of a triangle are a, b, and c, then area of a triangle is given by:

Where s = semiperimeter of the triangle

Area of a right-angled triangle Diagram:

Explanation:Area of park = Area of ΔBCD + Area of ΔABDΔBCD is a right-angled triangle. Therefore,Area of ΔBCD = 1/2 × 12 × 5 m2 = 30 m2InΔ ABD, we have2s = 9 + 8 + 13 = 30 ⇒ s = 15

∴

= 6√35 m2Area of park = (30 + 6√35) cm2Hence, the area of the park is (30 + 6√35) cm2.

answer ask from school teacher

65.4cm2 is the most correct answer

65.4cm2 is the right answer

96 is a answer of this question

65.4 is the correct answer

65.4cm2 is the most correct answer

65.4 is the correct answer

65 is the best ansewr

65.4 is the best answer

56 meter square units

56 meter square units

(30+√35)cm2 is the correct answer

65.4 is the correct answer

(30+√35)cm.^2 is correct answer

hiiiiiiiiiii friend nice question

area of park is (30+6√35)cm2

65.4 cm2 is this is answer

Hence, the area of the park is (30+6√35)cm2

pata nahin kya hai iska answer bhai

65.4 is the correct answer

65.4cm2 is the answer

Let side be 'a'volume of a cube=a*3a*3 =4913a= cube root of 4913=17cm

please like me do as best me i work very hard thanks