1. A box is of dimensions 2.4 m x 1-0 mx 75 cm. Find the volume of the

1.	1. A box is of dimensions 2.4 m x 1-0 mx 75 cm. Find the volume of the box.Given : length 1 = 2.4 m, breadth b = 1.0 mand height h = 75 cm = 0.75 m.Volume of box V = lxbxh
Answer» ${ \tt{ \large \bold{ \purple{given}}}}$ ${ \rm{the \: dimensios \: of \: a \: box \: are \to}}$ ${ \rm{length(l) = 2.4m}}$ ${ \rm{breadth(b) = 1.0m}}$ ${ \rm{volume(v) = 0.75m}}$ ${ \tt{ \large \bold { \blue{solution}}}}$ ${ \rm{ volume(v) = l \times b \times h}}$ ${ \rm{ = 2.4 \times 1.0 \times 0.75 \: {m}^{3} }}$ ${ \rm{ = 1.8 {m}^{3} }}$ ${ \rm {Ans \colon \:so \: the \: volume \: is \: 1.8 {m}^{3} }}$ ────────────────────────── ${ \rm{ \large{related \: formulas}}}$ ${ \rm{ \large{Perimeter \colon}}}$ ${ \rm{perimeter \: of \: square =4a }}$ ${ \rm{perimeter \: of \: rectangle =2(l + b) }}$ ${ \rm{perimeter \: of \: triangle =a + b + c }}$ ${ \rm{perimeter \: of \: circle=2 \pi r}}$ ${ \rm{ \large{Area \colon}}}$ ${ \rm{area \: of \: square = {a}^{2} }}$ ${ \rm{area \: of \: rectangle =l \times b }}$ ${ \rm{area\: of \: triangle = \frac{{h_b}b}{2} }}$ ${ \rm{area\: of \: circle = \pi \: {r}^{2} }}$ ${ \rm{ \large{Volume \colon}}}$ ${ \rm{volume \: of \: cube = {a}^{3} }}$ ${ \rm{volume \: of \: cuboid = l \times b \times h }}$ ${ \rm{volume \: of \: cylinder = \pi {r}^{2}h }}$ ${ \rm{volume \: of \: cone = \frac{1}{3} \pi {r}^{2}h }}$