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1. A ABC in which AB2. A PQR in which PQ=5.5 cm, QR = 6.5 cm, RP = 5 cm.3. A XYZ in which XZ = 8.4 cm, XY = 6.8 cm, YZ = 7.5 cm.4. A DEF in which DE = 8 cm, DF = 7.2 cm, EF = 6.3 cm.5. A LMN in which LN = 7 cm, NM=5.5 cm, LM= 6.4 cm |
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Answer» 1 . ABC is a TRIANGLE in which AB = Ac and D is a point on the SIDE AC such that BC2 = AC × CD. Prove that BD = BC. ABC is a triangle in which AB = Ac and D is a point on the side AC such that BC2 = AC × CD 2. taking P as centre and measure 5cm , cut an ARC . taking Q as centre and measure 6.5 cm , cut an arc name the point meeting as R . PQR is the required triangle . 3. Draw a line segment which is sufficiently long using ruler. (ii) Locate points X and Z on it such that XZ=9.5cm. (iii) With X as centre and radius 7.8cm, draw an arc(see figure) (iv) With Z as centre and radius 4.5cm , draw another arc cutting the previous arc at C. (v) Join XY and YZ 4 Step 1: Draw DE=8cm Step 2: With D as centre and radius =7.2cm, draw an arc at F. Step 3: With E as centre, and radius =6.3cm, draw an arc at F. Step 4: Join DF and EF. Hence, ΔDEF is the required triangle. 5 . Construct ΔLMN in which LN=7 cm, NM=5.5 cm, LM=6.4 cm. 6 0.04 metre |
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