1.

1.6 g of an organic compound gave 2.6 g of magnesium pyrophosphate. The percentage of phosphorus in the compound is

Answer»

0.4538
0.5438
0.3776
0.1902

Solution :% of `P=(62)/(222)XX(X)/(w)XX100=(62)/(222)xx(2.6)/(1.6)xx100=45.38%`


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