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1.575 gm of organic acid was dissolved in 250ml of water 20ml of this solution required 16 ml of N//8 alkali solution for completely neutralization. (M. wt of acid is 126) the basicity of acid is |
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Answer» 2ml 1 N alkali solution = 20ml of acid solution ? = 250 ML of acid solution `implies` % 25ml IN of alkali solution obtained 25ml 1N of alkali solution .......... 1.575grams of acid 1000ml 1 N alkali solution ........? `implies (1.575)/(25) xx 1000` GRAMS of acid `implies` equalant Acid = 63 Molecular WEIGHT of acid = `"equivalent acid" xx "VALANCY"` `implies` valancy = 2 126 = 63X valancy |
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