1.

1.5 g ofBa(NO_(3))_(2) dissolved in 100gofwatershows a depressionin freezing pointequal to 0.28^(@)C . Whatis the percentagedissociationof thesalt ? (k_(f)for water= 1.86 K//m and molar mass of Ba(NO_(3))_(2) = 261).

Answer»


SOLUTION :`M_(B) ` (OBSERVED) `= (1.86 XX 1000xx 1.5)/(0.280 xx 100)= 99.64`
` i=(261)/(99.64)= 2.62`
`Ba(NO_(3))_(2) hArr Ba^(2+) + 2NO_(3)^(-)`
`{:(,"Initial",1,0,0),(,"After dissociaiton ",1-alpha,alpha,2alpha):}`
` i=(1-alpha + alpha+2alpha)/(1) = 2.62`
`alpha = 81%`


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