(1)/(4)[Li_(CH_(3))_(4)]+[Mo(CO)_(6)] to [X] Here X is Lithium acetyl – InterviewSolution

1.	(1)/(4)[Li_(CH_(3))_(4)]+[Mo(CO)_(6)] to [X] Here X is Lithium acetylpentacarbonyllmolybdate(1-), then find the total number of Mo-C linkages in the complex X
Answer» SOLUTION :`X=Li[Mo(CH_(3)CO)(CO)_(5)]`

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