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1 3R x=3+ «8 हो, तो »* + - बेराबर |
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Answer» x = 3+ √8 x = (3+√8)(3-√8) / (3-√8) x = (9 -8) / (3-√8) x = 1/ (3 -√8) Or we can write1/x = (3-√8) Put the value and find out x² +(1/x²) = x² + (1/x)² So x² + 1/ x² = (3 +√8)² + (3 -√8)² = 9+6√8+8 + 9–6√8+8 =34 |
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