Saved Bookmarks
| 1. |
(1) 3? () 6' (1) 5! (V) (V20) In AABC, D is the mid point of BC IIDL IAB and DMLAC Such that DL DM,Prove that AB ACthanolynomial (+ X-T1x X+a) is divisible |
|
Answer» DL=DM (given)BD=CD (given)Angle BLD=Angle CMD (DL per. to AB and DM per. to AC)Therefore tri. BDL = tri. CDM (RHS)Angle B =angle C (by c.p.c.t.)Hence proved, AB = AC ( side opp. to equal angles are equal) |
|