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-1/2x^3/2 then if x=2 find its value

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-1/2x^3/2 then if x=2 FIND its VALUE

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\huge\bold{ =  -  \frac{1}{2}  {x}^{ \frac{3}{2} } }

Given x=2

=  > -   \frac{1}{2}  {(2)}^{ \frac{3}{2} }

=  >  -  \frac{1}{2}  \sqrt{2}  \times 2

\sqrt{2}  \times 2 =  {2}^{ \frac{1}{2}  + 1}  = 2 \frac{1 + 2}{2}  =  {2}^{ \frac{3}{2} }

=  >  -  \frac{1}{2}  \times  \sqrt{2}  \times 2

=  -  \sqrt{2}

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