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(1)2x^2-x+1/8=0(2) 2x^2+x-6=0 find roots of given quadratic equation by factorisation |
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Answer» Answer: roots of equations (1) 1/4 and 1/4 (2) 3/2 . -2 Step-by-step explanation: (1) 2x² - x + 1/8 = 0(16x² - 8x + 1)8 = 0 16x² - 8x + 1 = 0 × 8 16x² - 8x + 1 = 0 16x² - (4 + 4)x + 1 = 0 16x² - 4X - 4x + 1 = 0 4x(4x - 1).-1(4x - 1) = 0 (4x - 1)(4x - 1) = 0 4x - 1 = 0 . 4x - 1 = 0 4x = 1 . 4x = 1 x = 1/4 . x = 1/4 (2) 2x² + x - 6 = 02x² + (4 - 3)x - 6 = 0 2x² + 4x - 3X - 6 = 0 2X(x + 2).-3(x + 2) = 0 (2x - 3)(x + 2) = 0 2x - 3 = 0 . x + 2 = 0 2x = 3 . x = -2 x = 3/2 . x = -2
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