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(-1 %2B sqrt(3))/(1 %2B sqrt(3)) %2B (1 %2B sqrt(3))/(-1 %2B sqrt(3))=a %2B sqrt(3)*b |
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Answer» +1√3−1+√3−1√3+1=a+√3b Solving for a. Want tosolve for binstead? 1 Simplify3-13−1to22. \frac{\sqrt{2}}{\sqrt{3}+1}+\frac{\sqrt{3}+1}{\sqrt{3}-1}=a+\sqrt{3}b√3+1√2+√3−1√3+1=a+√3b 2 Subtract\sqrt{3}b√3bfrom both sides. \frac{\sqrt{2}}{\sqrt{3}+1}+\frac{\sqrt{3}+1}{\sqrt{3}-1}-\sqrt{3}b=a√3+1√2+√3−1√3+1−√3b=a 3 Switch sides. a=\frac{\sqrt{2}}{\sqrt{3}+1}+\frac{\sqrt{3}+1}{\sqrt{3}-1}-\sqrt{3}ba=√3+1√2+√3−1√3+1−√3b Done  |
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