1.26g of a dibasic acid were dissolved in water and the solution made upto 200ml. 20ml of this solution was completely neutralised by 10ml of N/5 NaOH solution. The molecular mass of the acid is

1.26g of a dibasic acid were dissolved in water and the solution made

1.	1.26g of a dibasic acid were dissolved in water and the solution made upto 200ml. 20ml of this solution was completely neutralised by 10ml of N/5 NaOH solution. The molecular mass of the acid is
Answer» tion:AnswerAs we know that,Normality = EQUIVALENT massmass of solute ×volume(L)Equivalent mass = N−factormolecular mass [ Here n FACTOR is 2 as it is DIBASIC acid ]Normality of dibasic acid = x1.26 × 2001000 N 1 = x6.3 ⇒ (x=eq.mass)By the formula,N 1 V 1 =N 2 V 2 x6.3 ×20=10× 51 26.3 ×20=x ⇒ x=68Equivalent mass = 63and molecular mass=63×2=126(2 is n−factor)