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-1,-22.(i)2x3 +x2-5x + 2: |
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Answer» 2x*x*x + x*x - 5x + 2 = 0 2x*x*x - 2x*x + 3x*x - 3x - 2x + 2 = 0 (2x*x + 3x - 2)(x-1) = 0 (2x*x + 4x - x - 2 )(x-1) = 0 (2x-1)(x+2)(x-1) = 0 x = -2,1,1/2 If you find this answer helpful then like it. |
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