1.216g of a sample of (NH_(4))_(2)SO_(4) was boiled with excess of NaOH and the ammonia gas so produced was absorbedin 100 mL of N H_(2)SO_(4) solution .The unreacted H_(2)SO_(4) requied 81.6 mL of normal solution of a base for exact neutralisation. Calculatepercentage amount of ammonia in ammonium sulphate .

1.216g of a sample of (NH_(4))_(2)SO_(4) was boiled with excess of NaO

1.	1.216g of a sample of (NH_(4))_(2)SO_(4) was boiled with excess of NaOH and the ammonia gas so produced was absorbedin 100 mL of N H_(2)SO_(4) solution .The unreacted H_(2)SO_(4) requied 81.6 mL of normal solution of a base for exact neutralisation. Calculatepercentage amount of ammonia in ammonium sulphate .
Answer» Solution :m.e of unreacted`H_(2)SO_(4)` = m.e of the base ` = 1 xx 81.6 = 81 .6` m.e of `NH_(3)` = m.e of `H_(2)SO_(4)` reacted with AMMONIA = m.e of total `H_(2)SO_(4)` - m.e of unreacted `H_(2)SO_(4)` ` = 1xx 100 - 81.6 = 18.4` ` :. ` equivalent of `NH_(3) = (18.4)/(1000) "" ...(Eqn.3)` Wt. of `NH_(3) = (18.4)/(1000) xx 17 "" ...(Eqn.4i)` ` = 0.3128 g ` ` :. " % o f " NH_(3)" in " (NH_(4))_(2)SO_(4) = (0.3128)/(1.216) xx100` ` = 25.72 % `