(1))! 2 tan’ 45°+C0s?30°- – InterviewSolution

1.	(1))! 2 tan’ 45°+C0s?30°-
Answer» tan45 = 1.cos 30 = (3^0.5)/2.sin60 = (3^0.5)/2Therefore, (cos30)^2 = (sin60)^2=> (cos30)^2 - (sin60)^2 = 0.=> 2(tan45)^2 + (cos30)^2 - (sin60)^2= 2(tan45)^2 + 0 = 2(1) = 2.

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