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1/2{sinA/1+cosA+1+cosA/sinA}=1/sinA |
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Answer» Step-by-step explanation: 1/2[sinA/1+cosA+1+cosA/sinA] 1/2[sin²A+(1+cosA)²/sinA(1+cosA)] 1/2[sin²A+1+cos²A+2cosA/sinA(1+cosA)] 1/2[2+2cosA/sinA(1+cosA)] 1/2[2/sinA] 1/sinA |
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