1.2.For what value of k will k + 9,2 -1 and 2k + 7 are the consecutive

1.	1.2.For what value of k will k + 9,2 -1 and 2k + 7 are the consecutive terms of an AP.? (For what value ofk will the canserutixe terme 7118)lr 1 lu n
Answer» Let,k + 9 = a2k - 1 = b2k + 7 = c To be in AP, a + c = 2b(k + 9) + (2k + 7) = 2(2k - 1)k + 9 + 2k + 7 = 4k - 23k + 16 = 4k - 23k - 4k = - 2 - 16- k = - 18k = 18 For k = 18, the terms k+9 , 2k - 1 , 2k + 7 are in AP Hope This helps you!

1.2.For what value of k will k + 9,2 -1 and 2k + 7 are the consecutive terms of an AP.? (For what value ofk will the canserutixe terme 7118)lr 1 lu n

Answer»

Let,k + 9 = a2k - 1 = b2k + 7 = c

To be in AP,

a + c = 2b(k + 9) + (2k + 7) = 2(2k - 1)k + 9 + 2k + 7 = 4k - 23k + 16 = 4k - 23k - 4k = - 2 - 16- k = - 18k = 18

For k = 18, the terms k+9 , 2k - 1 , 2k + 7 are in AP

Hope This helps you!