1.

1+2+3+---------+n/1+3+5+-------+(2n-1) what is the value​

Answer»

ANSWER:

\frac{(<klux>N</klux>+1)}{2n}

Step-by-step EXPLANATION:

[ 1+2+3+---------+n ] / [ 1+3+5+-------+(2n-1) ]

= \frac{n(n+1)}{2} / n²

= \frac{n(n+1)}{2n^2}

= \frac{(n+1)}{2n}


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