1^2+3^2+5^2+-----+(2n-1)^2=n(2n-1)(2n+1)/3

1.	1^2+3^2+5^2+-----+(2n-1)^2=n(2n-1)(2n+1)/3
Answer» L.H.S.Sum=1^2+2^2+---------+(2n-1)^2=sum(2n-1)^2=sum(4n^2+1-4n)=sum4n^2+sum(1)-sum(4n)=4[n(n+1)(2n+1)/6]+n-4n(n+1)/2=n/3[2(n+1)(2n+1)+3-6(n+1)]=n/3[4n^2+6n+2+3-6n-6]=n/3[4n^2-1]=n/3[(2n-1)(2n+1)]=n(2n-1)(2n+1)/3 Bhai rehne de

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