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1/15, 1/12, 1/10,....., to 11 terms |
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Answer» The given AP is 1/15, 1/12, 1/10........ 11 terms a = 1/15, d = 1/12 - 1/15 = (5 - 4)/60= 1/60 We know, sum of n terms Sn = n/2[2a + (n-1)d] Then, sum of 11 terms of given APS11 = 11/2[2*1/15 + 10*1/60] = 11/2[2/15 + 10/60] = 11/2[(8 + 10)/60] = 11/2(18/60) = 33/20 |
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