1.

1~ 100+ 99809 i ‘{I — ue} - ःहू 809

Answer»

SinA/secA+tanA-1+cosA/cosecA+cotA-1=sinA/(1/cosA+sinA/cosA-1)+cosA/(1/sinA+cosA/sinA-1)=sinA/{(1+sinA-cosA)/cosA}+cosA/{(1+cosA-sinA)/sinA}=sinAcosA/(1+sinA-cosA)+sinAcosA/(1+cosA-sinA)=sinAcosA[(1+cosA-sinA+1+sinA-cosA)/(1+sinA-cosA)(1+cosA-sinA)]=2sinAcosA/(1+sinA-cosA+cosA+sinAcosA-cos²A-sinA-sin²A+sinAcosA)=2sinAcosA/{1+2sinAcosA-(sin²A+cos²A)}=2sinAcosA/(1+2sinAcosA-1)=2sinAcosA/2sinAcosA=1 (Proved)

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