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1. (0) If f (x) log (I +x) and g(x)e, then value of (gof) (x) is |
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Answer» f(x) = log(1+x) g(x) = e^x (gof)(x) = g(f(x)) = g(log(1+x)) = e^(log(1+x)) = 1+x If you find this answer helpful then like it. |
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