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09. If sum of parallel sides of trapezium is 25 cm, find the height.any one who answer step by step i will mark him a brainiest |
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Answer» Answer =12The altitude of the TRAPEZIUM is 12 cm. Step-by-step explanation: The area of a trapezoid is given by A = \frac{1}{2} \times(\textrm {SUM of it's parallel SIDE lengths}) \times \textrm {Altitude}A= 2 1 ×(Sum of it’s parallel side lengths)×Altitude Now, it is given that the sum of the parallel sides lengths of the trapezium is 25 cm. and its area is 150 cm². If the altitude of the trapezium is h, then we can write \frac{1}{2} \times (25) \times h = 150 2 1 ×(25)×h=150 ⇒ h = 12 cm. Hence, the altitude of the trapezium is 12 cm. |
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