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.011. Solve for x.4V3x2 + 5x - 2y3 = 0(ii) x2 + 482 x + 6(1) 223 + 27 87(iv) 28222 + 4x + V2iv) ** -- 2V3x + 2 |
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Answer» 1) 4√3x^2+5x-2√3=04√3x^2+8x-3x-2√3=04x(√3x+2)-√3(√3x+2)=0(√3x+2)(4x-√3)=0either √3x+2=0√3x= -2x= -2/√3= 2√3/3or 4x-√3=04x= √3x= √3/4 2) x^2+4√2x+6=0x= -4√2+-√(4√2)^2-4×1×6/2 = -4√2+-√32-24/2 = -4√2+-√8/2 = -4√2+-2√2/2= -2√2/2= -√2x= -4√2-2√2/2 = -6√2/2= -3√2 = 4√2+2√2/2= (i)4V3x^2+5x-2V3; 4V3x^2+8x-3x-2V3=0; 4x(V3x+2)-V3( V3x+2); (4x-V3)(V3x+2)=0; 4x=V3; x=V3/4; x=-2/V3=2V3/3; 2)x^2+4V2+6=0; x=-4V2+V(4V2)^2-4x1x6/2 =0 =4V2+V32-24/2 =-4V2+V8/2=0 -2V2/2=-V2; x=-4V2-2V2/2=-3V2 |
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