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0. Ishaan moves along the boundary of a square playground of side 10 min 40 s. What will be his distance and magnitude of displacement at the end of 2 minutes 20 seconds from his initial position? |
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Answer» Answer: Distance = 35 metres MAGNITUDE of displacement = 5 metres Explanation: Given:- Length of side of square playground : 10 metres TIME taken to cover 10M boundary of ground : 40sec To Find:
(i) Distance travelled at the end of 2 min 20 sec from his initial position (ii) Magnitude of displacement at the end of 2 min 20 sec from his initial position Solution:- Seconds in 2 minutes 20 seconds = (2×60) + 20 = 140 seconds Ishaan covers 10 metres is 40 seconds...so his speedmust be equal to (10/40) , that's 0.25m/s. So in 140 seconds, Distance covered = 140 × 0.25 m (i) Distance covered = 35 metres EVERY side of the square is of length 10 metres, thus after 2 minutes 20 seconds , Ishaan must end up in the middle of 4th side of the square playground. Displacement is given by the net Distance between initial point & final point. (ii) Thus Magnitude of displacement = 5 metres. |
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