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0. Define and explain normality with mathematical expression.Calculate the normality of 500 ml of solution containing5.3 gm of Na2CO3. |
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Answer» Molecular MASS of Na 2
CO 3
=106 gmol −1
106 53
=0.05mol As 0.05 mol are dissolved in 500mL; Number of moles dissolved in 1000mL (1L) or molarity of TH solution = 500 0.05
×1000=0.1M. |
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