1.

0. Define and explain normality with mathematical expression.Calculate the normality of 500 ml of solution containing5.3 gm of Na2CO3.​

Answer»

EXPLANATION:

Molecular MASS of Na

2

CO

3

=106 gmol

−1

NUMBER of MOLES =

106

53

=0.05mol

As 0.05 mol are dissolved in 500mL;

Number of moles dissolved in 1000mL (1L) or molarity of TH solution

=

500

0.05

×1000=0.1M.



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