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0. Calculate the mole percentage of CH3OH and HO 2respectively in 60% (by mass) aqueous solution of CH3OH (1) 45.8, 54.2(2) 54.2. 45.8(3) 50, 50(4) 60, 40 |
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Answer» %CH3OH by mass =60% mass of CH3OH÷ mass of solution =60/100 Let, the mass of the solution be 100gm THEREFORE, mass of CH3OH=60gm and mass of H2O=40gm moles of CH3OH=60/32 moles of H2O=4O/18 % mole of CH3OH=( moles of CH3OH÷ TOTAL moles )X100=[60/32÷(60/32+ 40/18)]×100 =45.76% % mole of H20=100−45.76=54.24% |
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