1.

0.90 g of non-electrolyte was dissolved in 87.90 g of benzene. This raised the boiling point of benzene by 0.25^(@)C. If the molar mass of non-electrolyte is 103.0g mol^(-1), calculate the molat elevation constant for benzene.

Answer»


Solution :`M_(2)=(1000M_(b)w_(2))/(w_(1)DeltaT_(b))"or"K_(b)=(M_(2)w_(1)DeltaT_(b))/(1000w_(2))=("103 G MOL"^(-1)xx87.90g xx0.25K)/("1000 g kg"^(-1)xx0.90g)="2.515 K kg mol"^(-1).`


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