1.

0.85 g aqueous solution of NaNO_(3) is approximately 90% dessociated at 27^(@)C. Calculate the osmotic pressure (R=0.0821 L atm K^(-1) mol^(-1))

Answer»


Solution :Calculation of Van't HOFF factor
`NaNO_(3)hArrNa^(+)("aq")+NO_(3)^(-)("aq")`
`alpha=(i-1)/(n-1)or0.9=(i-1)/(2-1)or i=0.9+1=1.9`
STEP II. Calculation of osmotic PRESSURE
`"Initial no. of moles of "NaNO_(3)(n_(B))=((0.85g))/((85" g mol"^(-1)))=0.01mol`
`"Osmotic pressure "(pi)=iCRT=(i n_(B)RT)/V`
`=(1.9xx(0.01"mol")xx(0.0821" L atm"^(-1)mol^(-1))xx300K)/((0.1K))=4.68"atm".`


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