1.

0.75 g platinic chloride, a monoacid base on ignition gave 0.245 g playinum. The molecular weight of the base is

Answer»

`75.0`
`93.5`
`100`
`80.0`

Solution :`("Wt. of "B_(2)H_(2)PtCl_(6))/(2B+410)=("Wt. of Pt")/195`
`:. 0.75/(2B+410)=0.245/195 implies B=93.5`
EQ. wt. of base `=93.5`, since it is monoacidic.
`:.` Mol. Wt. of base `=93.5xx1=93.5`


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